Thursday, December 28, 2017

The concept of Nuclear Magnetic Spectroscopy

There is no denying the fact that Nuclei possessing angular moment known as spin have an associated magnetic moment. A few examples of magnetic isotopes are 13C, 1H, 19F,14N, 17O, 31P, and 33S. It may be focused that not every isotope is magnetic. In particular, we should also memo that 12C is not magnetic. If a nucleus is not magnetic, it can't be studied by nuclear magnetic resonance spectroscopy. For the purposes of this course, we will be most interested in 1H and 13C. I will limit my planning to 1H in this short handling.

Generally speaking, you should think of these special nuclei as tiny, atomic, bar magnets. Suffice it to say that Nuclear Magnetic Spectroscopy is based on the fact that when a population of magnetic nuclei is placed in an external magnetic field, the nuclei become aligned in a unsurprising and finite number of orientations. For 1H there are two orientations. In one orientation the protons are aligned with the external magnetic field (North Pole of the nucleus aligned with the south pole of the magnet and south pole of the nucleus with the north pole of the magnet) and in the other where the nuclei are aligned against the field (north with north, south with south). The alignment with the field is also called the "alpha" orientation and the alignment against the field is called the "beta" orientation. From my description of the poles, which orientation do you think is the preferred or lower in energy? If you guessed the "alpha", you are correct. It might be worth noting at this point that before the nuclei are placed in the magnetic field they have random orientation random orientation outside of field alpha and beta orientation in field Since the alpha orientation is preferred, more of the population of nuclei are aligned with the field than against the field. You might wonder why any spins would align against the field. Realize that we are talking about atomic magnets. These are very, very weak magnets. The energy difference between the alpha and beta orientations is not large. There is enough energy for nuclei to exchange between the two orientations at room temperature, though a slight excess on average is in the lower energy, alpha state. The nuclear magnetic resonance (NMR) spectroscopy experiment involves using energy in the form of electromagnetic radiation to pump the excess alpha oriented nuclei into the beta state. When the energy is removed, the energized nuclei relax back to the alpha state. The fluctuation of the magnetic field associated with this relaxation process is called resonance and this resonance can be detected and converted into the peaks we see in an NMR spectrum. What sort of electromagnetic radiation is appropriate for the low energy transition involved in NMR? Well believe it or not, radio waves do the trick. Radio waves are at the very low energy end of the electromagnetic spectrum and are sufficient to induce the desired transition. It is for this reason that NMR is considered to be a safe method of analysis. The same technology is now used in hospitals in MRI (Magnetic Resonance Imagining - people are afraid of the word nuclear). If you have ever had an MRI done, realize that you were placed in a magnetic field and all your magnetic nuclei lined up in the manner described above. Excess nuclei were pumped to higher energy states as you were exposed to radio waves. The following are two very, very important points to accept and learn if you are going to understand the rest of the discussion. 1. Electric currents have associated magnetic fields. 2. Magnetic fields can generate electric currents. If you haven't had physics yet, try to accept these two points. Certainly most people have at least heard of electromagnets and if so, you probably have some idea about the first statement. The following is a very important NMR relationship. This expression relates the external field to the frequency of resonance.

 In this equation, is frequency,  is the magnetogyric ratio (not needed for this discussion - a constant for each nucleus). The big thing to glean from this equation is that the external field and the frequency are directly proportional. If the external field is larger , the frequency needed to induce the alpha to beta transition is larger. It follows then that in a larger field, higher frequency radio waves would be needed to induce the transition. In this context, it is relevant to note that different nuclear magnetic resonance spectrometers have different magnetic field strengths. For example, the NMR on the first floor of Park Hall has a relatively high field, superconducting magnet. Because the field is high (high enough to erase bank cards and interfere with pacemakers and watches), the frequency range needed to excite protons is relatively high. It is called a 300 MHz (MHz = megahertz, a hertz is a cycle per second - a frequency unit) spectrometer, referring to the excitation frequency. The NMR on the second floor of Park Hall has a much weaker electromagnet associated with it. It is a 60 MHz instrument. Since different NMRs have different operating frequencies, spectra cannot be compared from different machines if they are reported in frequency units. For this reason, the universal ppm (parts per million) units are used in NMR. Please note the following relationship between ppm and frequency. The fact that frequency and ppm are directly proportional is all you need to retain for the future discussion and the course in general. Chemical shift in ppm = peak position in Hz (relative to TMS) spectrometer frequency in MHz Now let us use these basic ideas to better understand and interpret NMR spectra.

Sunday, September 3, 2017

A passage to time without end

A Passage to Time Without End

Be a child to learn from being innocent, to gain
It is knowledge to survive in eternity,
As if the world is full of perils and shocks;
To have the fortune to make the earth beautiful.
Very hard to achieve the goals as set by God
To perish every time to test the fortune of love
And watch over the creativity as set underneath
The meadow and the sky are the daughters
Of the earth as if  flashed over the moon
And inside the holes of the Sun in the galaxy, boom.
Be a child to shake off everything and every pile of love
In the watery ocean of plants and creepers;
As if we are bound with withes for everlasting growth
For the light grey and colourful world, ever since
To switch over to the pavements and rocks ahead.
In the world, it's so hard to know the unknown
By struggling so perilously, like death and torture
To show off the signals before the death traps
What had happened in the Datang of the Philippines?
For humanity and love for countrymen
A thousand soldiers sacrificed their lives for peace
Everlasting habitats will be virtually hereinafter.

Oxidation-Reduction Reactions



Rules for Assigning Oxidation States

The oxidation state (OS) of an element corresponds to the number of electrons, e-, that an atom loses, gains, or appears to use when joining with other atoms in compounds. In determining the OS of an atom, there are seven guidelines to follow:
1.    The OS of an individual atom is 0.
2.    The total OS of all atoms in: a neutral species is 0 and in an ion is equal to the ion charge.
3.    Group 1 metals have an OS of +1 and Group 2 an OS of +2
4.    The OS of fluorine is -1 in compounds
5.    Hydrogen generally has an OS of +1 in compounds
6.    Oxygen generally has an OS of -2 in compounds
7.    In binary metal compounds, Group 17 elements have an OS of -1, Group 16 of -2, and Group 15 of -3.
(Note: The sum of the OSs is equal to zero for neutral compounds and equal to the charge for poly atomic ion species.)

Example 1: Assigning OSs
Determine the OSs of the elements in the following reactions:
a.       Fe(s)+O2(g)→Fe2O3(g)
b.      Fe2+
c.       Ag(s)+H2SAg2S(g)+H2(g)

SOLUTIONS
A.     Fe and O2 are free elements; therefore, they each have an OS of 0 according to Rule #1. The product has a total OS equal to 0, and following Rule #6, O has an OS of -2, which means Fe has an OS of +3.
B.     The OS of Fe corresponds to its charge; therefore, the OS is +2.
C.     Ag has an OS of 0, H has an OS of +1 according to Rule #5, S has an OS of -2 according to Rule #7, and hence Ag in Ag2S has an OS of +1.

Example 2: Assigning OSs
Determine the OS of the bold element in each of the following:
A.     Na3PO3
B.     H2PO4-

SOLUTIONS
A.     The oxidation numbers of Na and O are +1 and -2. Because sodium phosphite is neutral, the sum of
B.      
C.     the oxidation numbers must be zero. Letting x be the oxidation number of phosphorus, 0= 3(+1) + x + 3(-2).
D.      x=oxidation number of P= +3. 
E.      Hydrogen and oxygen have oxidation numbers of +1 and -2. The ion has a charge of -1, so the sum
F.      of the oxidation numbers must be -1. Letting y be the oxidation number of phosphorus, -1= y + 2(+1) +4(-2), y= oxidation
G.     number of P= +5.

Example 3: Identifying Reduced and Oxidized Elements
Determine which element is oxidized and which element is reduced in the following reactions (be sure to include the OS of each): 
A.     Zn + 2H+ → Zn2+ + H2
B.     2Al + 3Cu2+→2Al3+ +3Cu
C.     CO32- + 2H+→ CO2 + H2O

SOLUTIONS
A.     Zn is oxidized (Oxidation number: 0 → +2); H+ is reduced (Oxidation number: +1 → 0)
B.     Al is oxidized (Oxidation number: 0 → +3); Cu2+ is reduced (+2 → 0)
C.     This is not a redox reaction because each element has the same oxidation number in both reactants and products:
D.      O= -2, H= +1, C= +4.
(For further discussion, see the article on oxidation numbers).
An atom is oxidized if its oxidation number increases, the reducing agent, and an atom is reduced if its oxidation number decreases, the oxidizing agent. The atom that is oxidized is the reducing agent, and the atom that is reduced is the oxidizing agent. (Note: the oxidizing and reducing agents can be the same element or compound).

Oxidation-Reduction Reactions

Redox reactions are comprised of two parts, a reduced half and an oxidized half, that always occur together. The reduced half gains electrons and the oxidation number decreases, while the oxidized half loses electrons and the oxidation number increases. Simple ways to remember this include the mnemonic devices OIL RIG, meaning "oxidation is loss" and "reduction is gain," and LEO says GER, meaning "loss of e- = oxidation" and "gain of e- = reduced." There is no net change in the number of electrons in a redox reaction. Those given off in the oxidation half reaction are taken up by another species in the reduction half reaction.
The two species that exchange electrons in a redox reaction are given special names. The ion or molecule that accepts electrons is called the oxidizing agent; by accepting electrons it causes the oxidation of another species. Conversely, the species that donates electrons is called the reducing agent; when the reaction occurs, it reduces the other species. In other words, what is oxidized is the reducing agent and what is reduced is the oxidizing agent. (Note: the oxidizing and reducing agents can be the same element or compound, as in disproportionate reactions).
A good example of a redox reaction is the thermite reaction, in which iron atoms in ferric oxide lose (or give up) O atoms to Al atoms, producing Al2O3.
Fe2O3(s)+2Al(s)→Al2O3(s)+2Fe(l)
Another example of the redox reaction is the reaction between zinc and copper sulfate.

Example 4: Identifying Oxidized Elements
Using the equations from the previous examples, determine what is oxidized in the following reaction.
Zn+2H+→Zn2++H2
SOLUTION
The OS of H changes from +1 to 0, and the OS of Zn changes from 0 to +2. Hence, Zn is oxidized and acts as the reducing agent.

Example 5: Identifying Reduced Elements
What is reduced species in this reaction?
Zn+2H+→Zn2++H2
SOLUTION
The OS of H changes from +1 to 0, and the OS of Zn changes from 0 to +2. Hence, H+ ion is reduced and acts as the oxidizing agent.

Combination Reactions

Combination reactions are among the simplest redox reactions and, as the name suggests, involves "combining" elements to form a chemical compound. As usual, oxidation and reduction occur together. The general equation for a combination reaction is given below:
A+BAB
Example 6: Combination Reaction
Equation: H2 + O2 → H2O
Calculation: 0 + 0 → (2)(+1) + (-2) = 0
Explanation: In this equation both H2 and O2 are free elements; following Rule #1, their OSs are 0. The product is H2O,
which has a total OS of 0. According to Rule #6, the OS of oxygen is usually -2. Therefore, the OS of H in H2O must be +1.

Decomposition Reactions

A decomposition reaction is the reverse of a combination reaction, the breakdown of a chemical compound into individual elements:
ABA+B
Example 7: Decomposition Reaction
Consider the decomposition of water:
H2OH2+O2
Calculation: (2)(+1) + (-2) = 0 → 0 + 0
Explanation: In this reaction, water is "decomposed" into hydrogen and oxygen. As in the previous example the
 H2O has a total OS of 0; thus, according to Rule #6 the OS of oxygen is usually -2, so the OS of hydrogen in H2O must be +1.

Single Replacement Reactions

A single replacement reaction involves the "replacing" of an element in the reactants with another element in the products:
A+BCAB+C
Example 8: Single Replacement Reaction
Equation:
Cl2+NaBr−−−→NaCl−−+Br2
Calculation: (0) + ((+1) + (-1) = 0) -> ((+1) + (-1) = 0) + 0
Explanation: In this equation, Br is replaced with Cl, and the Cl atoms in Cl2 are reduced, while the Br ion in NaBr is oxidized.

Double Replacement Reactions

A double replacement reaction is similar to a double replacement reaction, but involves "replacing" two elements in the reactants, with two in the products:
AB+CDAD+CB
Example 9: Double Replacement Reaction
Equation: Fe2O3 + HCl → FeCl3 + H2O
Explanation: In this equation, Fe and H trade places, and oxygen and chlorine trade places.

Combustion Reactions

Combustion reactions almost always involve oxygen in the form of O2, and are almost always exothermic, meaning they produce heat. Chemical reactions that give off light and heat and light are colloquially referred to as "burning."
CxHy+O2CO2+H2O
Although combustion reactions typically involve redox reactions with a chemical being oxidized by oxygen, many chemicals "burn" in other environments. For example, both titanium and magnesium burn in nitrogen as well:
2Ti(s)+N2(g)→2TiN(s)
3Mg(s)+N2(g)→Mg3N2(s)
Moreover, chemicals can be oxidized by other chemicals than oxygen, such as Cl2 or F2; these processes are also considered combustion reactions

Disproportionate Reactions

Disproportionate Reactions: In some redox reactions a single substance can be both oxidized and reduced. These are known as disproportionate reactions, with the following general equation:
2AA+n+An
Where n is the number of electrons transferred. Disproportionate reactions do not need begin with neutral molecules, and can involve more than two species with differing oxidation states (but rarely).


Disproportionate reactions have some practical significance in everyday life, including the reaction of hydrogen peroxide,
 H2O2 poured over a cut. This a decomposition reaction of hydrogen peroxide, which produces oxygen and water
. Oxygen is present in all parts of the chemical equation and as a result it is both oxidized and reduced. The reaction is as follows:
2H2O2(aq)→2H2O(l)+O2(g)
Explanation: On the reactant side, H has an OS of +1 and O has an OS of -1, which changes to -2
for the product H2O (oxygen is reduced), and 0 in the product O2 (oxygen is oxidized).

Ammonia and the Haber Process

Ammonia (NH3) is a covalent compound and is an extremely useful chemical. It is commonly used to make: nitrogenous fertilisers which is v...